Kenneth = 2+5+5+5+5+2+8 = 32 (Ken = 2+5+5 = 12)
Joseph = 1+6+1+5+7+8 = 28/37
Howard = 8+6+5+1+9+4 = 33
Jr . = 1+9 = 10
Kenneth Joseph Howard Jr. = 103/112
Ken Howard = 45
Kenneth = 2+5+14+14+5+20+8 = 68 (Ken = 11+5+14 = 30)
Joseph = 10+15+19+5+16+8 = 73
Howard = 8+15+23+1+18+4 = 69
Jr. = 10+18 = 28
Kenneth Joseph Howard Jr. = 238
Ken Howard = 99
3/28/1944 = 3+28+19+44 = 94
3/28/1944 = 3+28+(1+9+4+4) = 49
3/28/1944 = 3+2+8+1+9+4+4 = 31
3/28/44 = 3+28+44 = 75
3/23/2016 = 3+23+20+16 = 62
3/23/2016 = 3+23+(2+0+1+6) = 35
3/23/2016 = 3+2+3+2+0+1+6 = 17
3/23/16 = 3+23+16 = 42
Also, his place of birth connects to '42', like his date of death.
El Centro, CA = 5+3+3+5+5+2+9+6+3+1 = 42
The Fibonacci Number that follows 144 is 233, a lot like the date March 23, written 23/3.
http://www.latimes.com/entertainment/envelope/cotown/la-et-ct-ken-howard-actor-and-president-of-sag-aftra-dead-at-71-20160323-story.html
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